What is the equation of the line that passes through these points: (-6, -13) and (6, -1)
m = (y2 - y1) / (x2 - x1) = (-1 -13) / (6 - -6) = -14 / 12 = -7/6
y - 13 = (-7 / 6) ( x - -6)
y + 13 + ( -7 /6) ( x - -6)
I'm not sure where to go after this point.....
+130511 You have the slope a little incorrect ...we have (-13 - -1) /(-6-6) = (-13 +1) /(-12) = -12/-12 = 1....whew!!! that makes things easier !!! so we have.......
y - (-13) = (1) ( x - (-6)) simplify
y + 13 = x + 6 subtract 13 from both sides
y = x + 6 - 13 simplify
y = x - 7 that's slope-intercept form .........add 7 to both sides and subtract y from both sides
7 = x - y → x - y = 7 and that's standard form
Hope that helps.....BTW.....you can "plug" in the points to make sure the equation is correct....I think you will find it is....
+130511 You have the slope a little incorrect ...we have (-13 - -1) /(-6-6) = (-13 +1) /(-12) = -12/-12 = 1....whew!!! that makes things easier !!! so we have.......
y - (-13) = (1) ( x - (-6)) simplify
y + 13 = x + 6 subtract 13 from both sides
y = x + 6 - 13 simplify
y = x - 7 that's slope-intercept form .........add 7 to both sides and subtract y from both sides
7 = x - y → x - y = 7 and that's standard form
Hope that helps.....BTW.....you can "plug" in the points to make sure the equation is correct....I think you will find it is....
