One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 48$ and $a^2 = 24$. What is the value of $b$ in this ordered pair?
ab^4 = 48 square both sides
a^2 b^8 = 2304
a^2 = 24
24 b^8 = 2304
b^8 = 2304 / 24
b^8 = 96
b = ± 96^(1/8)
+866 
