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One ordered pair $(a,b)$ satisfies the two equations $ab^4 = 48$ and $a^2 = 24$. What is the value of $b$ in this ordered pair?

 Apr 1, 2024
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ab^4  = 48         square both sides

a^2 b^8  = 2304

 

a^2  = 24

 

24 b^8  =  2304

b^8  =  2304 /  24

b^8 = 96

 

b = ± 96^(1/8) 

 

cool cool cool

 Apr 1, 2024

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