+1839 Solve the inequality x^3 + 4x > 5x^2 + 28x + x^3. Write your answer in interval notation.
+399 \(0>5x^2+24x\)
\(x(5x+24)<0\)
Take interval between two solutions, because quadratic points up, and you want the part below the x axis.
Therefore the interval is \((-\frac{24}{5}, 0)\).
