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The concession stand at a football game sells hotdogs and burgers. Each burger costs 2.35 and hotdogs cost 1.10 per hot dog. The concession stand sold a total of $294.20 worth of hot dogs and burgers by
the end of the game. By the end of the game people had consumed 172 hot dogs and burgers in total.  How many of each were sold?

 Mar 19, 2021

Best Answer 

 #1
avatar+91 
+2

Let b represent the number of burgers sold.

Let h represent the number of hot dogs sold.

 

Note that:

2.35b+1.10h = 294.20

b+h=172

 

b+h=172

h=172-b

 

Now solve the system of equations with substitution:

 

2.35b+1.10h = 294.20

2.35b+1.10(172-b) = 294.20

2.35b + 189.2 - 1.1b = 294.20

1.25b=105

b=84

 

b+h=172

84+h=172

h=88

 

Therefore there are 84 burgers and 88 hot dogs.

Solved! :)

 Mar 19, 2021
 #1
avatar+91 
+2
Best Answer

Let b represent the number of burgers sold.

Let h represent the number of hot dogs sold.

 

Note that:

2.35b+1.10h = 294.20

b+h=172

 

b+h=172

h=172-b

 

Now solve the system of equations with substitution:

 

2.35b+1.10h = 294.20

2.35b+1.10(172-b) = 294.20

2.35b + 189.2 - 1.1b = 294.20

1.25b=105

b=84

 

b+h=172

84+h=172

h=88

 

Therefore there are 84 burgers and 88 hot dogs.

Solved! :)

ArithmeticBrains1234 Mar 19, 2021

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