+0  
 
0
38
5
avatar

How would you solve this?

 

\(\binom40+\binom51+\binom62+\binom73\)

 Feb 2, 2020
 #1
avatar
0

Just evaluate them one by one and should get:

 =56

 Feb 2, 2020
 #2
avatar
0

If you beleive everything that people, especially anonymous guests, tell you on the internet then you are as stupid as they are.

 Feb 2, 2020
 #3
avatar
0

 

That's funny, because it's an anonymous guest who is saying it. 

.

Guest Feb 2, 2020
 #4
avatar+20216 
0

   = 1  +  5  +  15  +  35     = 56

 Feb 2, 2020
 #5
avatar+107414 
0

If they are vectors then you would just add the top and then add the bottom

 

If it is for combinatory maths then EP has answered.

 Feb 3, 2020

17 Online Users

avatar
avatar