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the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the length is 60 yards more than the width
Guest Mar 7, 2012
 #1
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l: length
w: width

two equations:

2*(l+w)=700
l=w+60


2*((w+60)+w)=700
2*( w+60+w)=700
2*( 2*w+60)=700
4*w+120=700
4*w+120-120=700-120
4*w=580
4*w/4=580/4
w = 145
l= 145+60 = 205

test:
2*( 145+205 ) = 2*(350) = 700
admin  Mar 7, 2012

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