We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
+1
63
4
avatar

Suppose ten distinct, positive integers have a median of $10$. ("Distinct integers" means that no two integers are the same.) What is the smallest the average of those ten integers could be? Explain your answer in complete sentences.

 Jun 13, 2019
 #1
avatar+25 
-3

Ok so Let us start with the smallest numbers that some can be...

which is naturally 1,2,3,4,5.

then, we place a ten down, and make the 4 next integers: 11,12,13,14,

1,2,3,4,5,10,11,12,13,14

calculating the average: 1+2+3+4+5=15

                                       10+11+12+13+14=60

15+60=65

65/10

6.5

 Jun 13, 2019
 #2
avatar+25 
-2

right? can somebody check my work?

ProffesorNobody  Jun 13, 2019
 #3
avatar
+1

The "median" in not 10 in your sequence but:

[10 + 5] / 2 =7.5

 Jun 13, 2019
edited by Guest  Jun 13, 2019
 #4
avatar+25 
-3

ohhh sorry... :(

ProffesorNobody  Jun 13, 2019

5 Online Users

avatar