Find all $x$ so that neither $-2(6+2x)\le -16-x+8-5x$ nor $-3x\ge 18-7x+25$.
Simplifying the given inequalities, we find [-7x \le 20 \qquad \text{and} \qquad -4x \le 36.]Both inequalities are satisfied for x≥−5, so the answer is x≥−5.