y∝ 1 √x If y=7 when x=36 find, y when x=4
Not sure if this is meant to be (1) y∝ √x or (2) y∝ 1/√x
If (1): y = k*√x 7 = k√36 7 = 6k k = 7/6 y = (7/6)*√4 y = (7/6)*2 y = 7/3
If (2): y = k/√x 7 = k/√36 7 = k/6 k = 42 y = 42√4 y = 42*2 y = 84
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