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y∝ 1 √x If y=7 when x=36 find, y when x=4

Guest Sep 27, 2017

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 #1
avatar+26233 
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Not sure if this is meant to be  (1) y∝ √x or (2) y∝ 1/√x

 

If (1):   y = k*√x         7 = k√36      7 = 6k    k = 7/6      y = (7/6)*√4      y = (7/6)*2     y = 7/3

 

If (2):    y = k/√x         7 = k/√36     7 = k/6   k = 42      y = 42√4     y = 42*2     y = 84

.

Alan  Sep 27, 2017
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1+0 Answers

 #1
avatar+26233 
+5
Best Answer

Not sure if this is meant to be  (1) y∝ √x or (2) y∝ 1/√x

 

If (1):   y = k*√x         7 = k√36      7 = 6k    k = 7/6      y = (7/6)*√4      y = (7/6)*2     y = 7/3

 

If (2):    y = k/√x         7 = k/√36     7 = k/6   k = 42      y = 42√4     y = 42*2     y = 84

.

Alan  Sep 27, 2017

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