help math problem

I am suspicious that the question was not copied correctly but here is the answer for this question.

3 ^x+ 2 + 9 ^x + 1 = 810

3 ^x+ (3 ²) ^x +3 = 810

3 ^x + (3 ^x ) ²+ 3 = 810

(3 ^x) ² + (3 ^x) -807 = 0

let y=3 ^x

y ² + y -807 = 0

Using the quadratic formuls you end up with

y = [-1 +- sqr(3229)] / 2

y-2 = [-5 +- sqr(3229)] / 2
so
3 ^x - 2 = [-5 +- sqr(3229)] / 2

im sorry its

3^x-3

my mistake

Which bit is 3^x-3 ?

Do you still need help or is it all sorted now?