+0  
 
+1
68
2
avatar+325 

In rectangle ABCD, shown here, \(\overline{CE}\) is perpendicular to \(\overline{BD}\). If \(BC = \sqrt 3\) and \(DC = 3\), what is CE?

 Feb 22, 2021
 #1
avatar
0

By similar triangles, CE = sqrt(3)/2.

 Feb 22, 2021
 #2
avatar
0

CE = 3√3 / √12

 Feb 22, 2021

15 Online Users

avatar
avatar
avatar
avatar