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image is question.

 Feb 13, 2019
 #1
avatar+37146 
0

You are given what y is equal to in the first equation....use this value in the second equation.

 

2x + 3 (x-8) = 1      solve for 'x'

2x + 3x - 24 = 1

5x = 25

x = 5               now use this value of x in EITHER of the equations to find  y

 

y = x -8

y = 5-8

y=-3

 Feb 13, 2019
 #3
avatar+140 
+1

so the problem has infinite numbers of solutions right?

Mclovin123  Feb 13, 2019
 #2
avatar+2863 
+4

y=x-8

2x=3y=1

 

2x+3(x-8)=1

 

2x+3x-24=1

 

5x-24=1

 

5x=25

 

\(\boxed{x=5}\), then plug it in to one of the equations

 

y=x-8

 

y=5-8

 

\(\boxed{y=-3}\)

 Feb 13, 2019
edited by CalculatorUser  Feb 13, 2019
 #4
avatar+140 
0

so the problem has infinite numbers of solutions right???

Mclovin123  Feb 13, 2019
 #5
avatar+2863 
+3

No this problem has ONE solution, the ordered pair (5,-3) is the ONLY solution. So ONE solution

 Feb 13, 2019
 #6
avatar+140 
0

But cant the solution also be (4,14) ??

Mclovin123  Feb 13, 2019
 #7
avatar+140 
0

oooh nvm ok thank you

Mclovin123  Feb 13, 2019
 #9
avatar+37146 
0

These are equations for lines......where they cross (intersect) is the solution to the system......straight lines only intersect at one point....one solution.

ElectricPavlov  Feb 13, 2019
edited by ElectricPavlov  Feb 13, 2019
 #8
avatar+2863 
+3

Sorry i didn't see your reply

 Feb 13, 2019
edited by CalculatorUser  Feb 13, 2019

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