i^11 + i^111
Here's another method you might find easier :
Note i^2 = -1
i^11 = i^10 * i = ( i^2 )^5 * i = (-1)^5 * i
And - 1 raised to an odd power = -1
So....we have (-1) * i = - i
Likewise
i^111 = i^110 * i = (i^2)^55 * i = (-1)^55 * i = -1 * i = -i
So
i^11 + i^111 =
-i + -i =
-2i