+257 What is the equation, in point-slope form, for a line that goes through (8, −4)(8, −4) and has a slope of −56−56 ?
y−4=−56(x+8)y−4=−56(x+8)
y+4=−56(x+8)y+4=−56(x+8)
y+4=−56(x−8)y+4=−56(x−8)
y−4=−56(x−8)
+36915 y = mx+b
y= 56 (8) + b
-4 = 448 + b so b = -452
y = 56 ( x -8) - 4
or, re-arranging:
y+4 = 56 (x-8)
