help me just for the homework plsssss

parallel to 3x+4y=12 through (4,-5)

This is the form we want  →   y = mx + b       where  m = the slope

We want y by itself on the left side......so

4y  = -3x + 12      divide both sides by 4

y  = (-3/4)x  + 3       so the slope is (-3/4)

And parallel lines have the same slope...so...uing the point-slope form ,we have

y - (-5)  = (-3/4)(x - 4)

y + 5  = (-3/4)x + 3       subtract 5 from both sides

y = (-3/4)x - 2

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parallel to : 1x+2y=5 through (-6,2)

Again, get y on the left side

2y  = -1x + 5     divide through by 2

y = (-1/2)x + 5/2   

So the slope = -1/2........now just folllow what I did in the first problem

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parallel to y=-2/5x-10 through (10,-3)

Here, we already have the form we need.......the slope is (-2/5)....and this is worked just like the other two