Tom and Peter have some money. The price of game cartridge is $45. If Tom buys this game cartridge, the ratio of his money left to that of Peter's will be 1:3. However, if Peter buys the game cartridge, the ratio of his money left to that of Tom's is 3:5. How much money does each boy have at first?
+118609 A please would have helped, but look at it like this
\(\frac{T-45}{P}=\frac{1}{3}\qquad and \qquad \frac{P-45}{T}=\frac{3}{5}\)
Now solve them simultaneously.
\( {T - 45 \over p} = {1 \over 3}\)
3(T-45) = P
3T - 135 = P
3T - P = 135 --(1)
\( {P - 45 \over T} = {3 \over 5}\)
5(p-45) = 3T
5P=225+3T
5P-3T=225 --(2)
Add equation (1) and (2)
3T-P=135 3-P=135
-3T+5P=225 -3+5P=225
------------------
4P=360
P=360/4=90
Put P=90 in equation (1)
3T-90=135
3T=135+90
T=225/3=75
P=90
T=90
+118609 Guest, please do not answer over the top of me.
I give partial answers for a reason and the asker is always encouraged to ask for more help if required.
I do not want this to be just a cheat site.
I want it to be a teaching / help site. I think that is what most of the answerers here would want.
If you want to answer a question in full that is fine, but choose one, of the many, that does not already have a correct partial answer.
Thank you.
+118609 ok, sorry
You need to identify yourself next time.
If you become a member that would be the easiest way.
Plus if you make a good impression your questions will be answered better and quicker.
I have not looked at your answer in any great detail but it looks fine to me. (I don't have my solution anymore)
