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Jason, Edward and Sam had a total of $837. Jason had the least amount of money. The ratio of Edward's money to Sam's money was 4:3 at first. Jason and Edward each spent 1/3 of their money. Given that the three boys had $648 left, how much did Jason have at first?

 Aug 11, 2021
 #1
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x = jason , y = edward, z = sam

x + y + z = 837 

x < y, z

y : z = 4 : 3

(2/3)x + (2/3)y + z = 648. 

2x + 2y + 3z = 1944

x + y + (3/2)z = 972

0.5z = 153, so z = 306

y = 408

so x = 123

 Aug 11, 2021
 #2
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holdup, sorry, theres a typo cheeky, 0.5z is supposed to equal to 135, so z = 270. so y = 360, so x = \(207\).

 

N O T   T H E      A N S W E R   123

Guest Aug 11, 2021
 #3
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Become a member

Guest Aug 11, 2021
edited by Guest  Aug 11, 2021
 #4
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cant, sorry :(

Guest Aug 11, 2021
 #5
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How?

Guest Aug 12, 2021
 #6
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not allowed to :/

Guest Aug 12, 2021
 #7
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You can't register?

mitgliedd1  Aug 12, 2021
edited by Guest  Aug 12, 2021

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