Write \(a^4-3a^2+9\) as a product of two monic quadratics with integer coefficients.
The expression is just the square of a binomial, so you can write a^4 - 3a^2 + 9 = (a^2 - 3)(a^2 - 3).
Unfortunately, that is incorrect, if you expand your answer you would get a^4-6a^2+9, nice try though!!
\(= (a^2 - 3a + 3)(a^2 + 3a + 3)\)
