Find the distance (in simplest radical form) between the two points: (5, -2) and (3, -6)

Hi MG,

Basically I meant that you can do CPhill's answer only you could write it in LaTex. (That was before CPhill's answer was even there)

Here is another one that you could have a go at finishing MathsGod1.  

It has a couple of new symbols for you too :)

the formula is

$$\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\
where\\
x_1=5,\quad x_2=3, \quad y_1=-2, \quad y_2=-6\\$$

you can plug the numbers in anon :)

CODING For MG    

\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\

where\\

x_1=5,\quad x_2=3, \quad y_1=-2, \quad y_2=-6\\

Thanks Melody

I got the answer d=66

I'm not sure if I did it correctly and if that's the answer :/

d = √[ (5 - 3)^2 + ( -6 - -2)^2 ] =

 √[ (5 - 3)^2 + ( -6 + 2)^2 ]  =

 √[ (2)^2 + ( -4) ^2]  =

√ [ 4 + 16 ]  =

√20 =

√(4 * 5) =

2√5

No anon, i guess you made a mistake   

How copy? Copy & Paste?

Thanks CPhill. I understand what you did there!