+140 plz help me solve this problem Assuming that\(3u + 12v\neq0\) , simplify \(\dfrac{12u^3 + 48u^2v}{3u+12v}\) . Can you give me a step by step explanation
+310 Factor the top term and bottom to get:
\(\frac{12u^2(u+4v)}{3(u+4v)}\)
Now we can cancel out the term (u+4v) since the problem tells us that this doesn't equal 0 (division by 0 is undefined)
\(\frac{12u^2}{3}\)
Now simplify to get:
\(4u^2\)
