Help me please
Radicals: find the principal roots by factoring
1296
Roots:
OK, Manuel
1296 is even, so it's divisible by 2
648 * 2 factor 648
324 * 2 * 2 factor 324
162 * 2 * 2 * 2 factor162
81 * 2 * 2 * 2 *2 factor 81
9 * 9 * 2 * 2 * 2 * 2 factor both 9's
3 * 3 * 3 * 3 * 2 * 2 * 2 * 2 =
34 * 24 [ 3 and 2 are both prime.....no further integer factorization is possible ]
Now if we wanted √1296, we would have √[ 34 * 24] =
√3^2 * √3^2 * √ 2^2 * √2^2 =
√9 * √9 * √4 * √4 =
3 * 3 * * 2 * 2 =
36
Check for yourself that 36^2 = 1296