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Help me, please.

 

Exercises: Perform the operations indicated.

 

x2y-2/3/x0y-1/3

ManuelBautista2019  Feb 7, 2018

Best Answer 

 #1
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+1

simplify  [x^2y^(-2/3)] / [x^0y^(-1/3)]

 

[x^2*y^-2/3] / [x^0* y^(-1/3)]

x^2 / [1 * y^(-1/3) * y^(2/3)]

x^2 / [y^(-1/3 +2/3)]

x^2 / y^1/3

Guest Feb 7, 2018
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1+0 Answers

 #1
avatar
+1
Best Answer

simplify  [x^2y^(-2/3)] / [x^0y^(-1/3)]

 

[x^2*y^-2/3] / [x^0* y^(-1/3)]

x^2 / [1 * y^(-1/3) * y^(2/3)]

x^2 / [y^(-1/3 +2/3)]

x^2 / y^1/3

Guest Feb 7, 2018

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