Help Me, please.
Solve: Evaluate the Following.
6C3
\(\begin{array}{|rcll|} \hline \mathbf{_6C_3} &=& \dbinom{6}{3} \\\\ &=& \dfrac{6}{3}\cdot \dfrac{5}{2}\cdot \dfrac{4}{1} \\\\ &=& 5\cdot 4 \\\\ &\mathbf{=}& \mathbf{20} \\ \hline \end{array}\)
