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Given 649-10-07-00-00_files/i0190000.jpg and 649-10-07-00-00_files/i0190001.jpg ; find 649-10-07-00-00_files/i0190002.jpg .

Guest Feb 4, 2015

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Best Answer

+128473

+5

In this quadrant, if tangent Θ = -2, then y = 2 and x = -1 and r =√5

Then, cos2Θ = cos^2Θ - sin^2Θ

And we have

cosΘ = -1/√5 sinΘ = 2/√5 .... so ....

cos^2Θ - sin^2Θ =

1/5 - 4/5 = -3/5 = -.6

CPhill Feb 4, 2015

1⁺⁰ Answers

+128473

+5

Best Answer

In this quadrant, if tangent Θ = -2, then y = 2 and x = -1 and r =√5

Then, cos2Θ = cos^2Θ - sin^2Θ

And we have

cosΘ = -1/√5 sinΘ = 2/√5 .... so ....

cos^2Θ - sin^2Θ =

1/5 - 4/5 = -3/5 = -.6

CPhill Feb 4, 2015

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