What is the value of n such that: \( 10^n = 10^{-6}\times \sqrt{\frac{10^{46}}{0.0001}}?\)
\(0.0001 = 10^{-4}\\ \frac{10^{46}}{10^{-4}}=10^{50}\\ \sqrt{10^{50}}=10^{25}\\10^{-6}\times 10^{25}=10^{19}\\\text{ Hence : }n=19\)
