Find three consecutive even integers such that the sum of the smallest integer and twice the second is 12 more than the third.
+130517 Find three consecutive even integers such that the sum of the smallest integer and twice the second is 12 more than the third.
Let x be the first integer, x +2 be the second and x + 4 the third ....so ....
x + 2(x + 2) = (x + 4) + 12 simplify
x + 2x + 4 = x + 16
3x + 4 = x + 16 subtract x, 4 from both sides
2x = 12 divide by 2 on both sides
x = 6
x + 2 = 8
x + 4 = 10
+130517 Find three consecutive even integers such that the sum of the smallest integer and twice the second is 12 more than the third.
Let x be the first integer, x +2 be the second and x + 4 the third ....so ....
x + 2(x + 2) = (x + 4) + 12 simplify
x + 2x + 4 = x + 16
3x + 4 = x + 16 subtract x, 4 from both sides
2x = 12 divide by 2 on both sides
x = 6
x + 2 = 8
x + 4 = 10
