Help Me please

Probability: Find these probabilities

1) In a bag of Solid-colored marbles, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange. What is the probability of getting 3 yellow marbles if 3 taken at a time?

2)In a bag of Solid-colored marbles, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange. What is the probability of getting 1 brown and 2 orange marbles if 3 are taken at a time?

3)In a bag of Solid-colored marbles, there are 5 brown, 6 yellow, 4 blue, 3 green, and 2 orange. What is the probability of getting 1 green marble if only 1 is taken at a time?

ManuelBautista2019
Apr 9, 2018

#1**+1 **

1) P(3 yellow)

We have 20 marbles in total

The number of sets that can be made is by choosing any 3 of the 20= C(20, 3) = 1140

The set we are interested in is the one where we choose any 3 of the 6 yellow marbles =

C(6,3) = 20

So.....the probability is 20 / 1140 = 2/114 = 1/57 ≈ .0175

2) P ( 1 brown and 2 orange)

We have 5 ways to choose a brown one

And we have only 1 way of selecting both orange marbles

So...the probability is

[ 5 * 1 ] / 1140 = 5/1140 = 1/228 ≈ .0044

3) P( 1 green) = 3/20 = .15

CPhill
Apr 9, 2018