If twice the present age of pedro is decreased from petra's age 5 years ago, the result is 4. Nine times pedro's age 3 years ago exceeds 4 times Petra's present age by 4. What are their ages last year?

Guest Nov 15, 2015

#1**+10 **

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Let Pedro's age today be Y

and Petra's age today be X

If twice the present age of pedro (2Y) is decreased from petra's age 5 years ago (X-5), the result is 4.

(X-5) - 2Y = 4

X-5 - 2Y = 4

X - 2Y = 9 times 4 because I am going to use it with (2) below.

4X - 8Y = 36 (1)

Nine times pedro's age 3 years ago [9(Y-3)] exceeds 4 times Petra's present age [ 4X] by 4.

9(Y-3) - 4X = 4

9Y-27 - 4X = 4

9Y - 4X = 31

- 4X +9Y = 31 (2)

(1)+(2)

0+Y = 67

Pedro is 67 now

4X-8*67=36

4X=36+536

4X=572

X=143

Petra is 143 and Pedro is 67

check

If twice the present age of pedro (2Y) is decreased from petra's age years ago (X-5) , the result is 4.

138 - 2*67 = 138-134 = 4 good

Nine times pedro's age 3 years ago [9(Y-3)] 9*64 = 576 exceeds 4 times Petra's present age [ 4X=4*143=572] by 4.

576-572=4 good

So that is correct I believe.

So last year Petra was 142 and Pedro was 66 years old. Maybe they are sea turtles. Sea turtles live a long time.

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Here is the earlier answer It was only a few post back so maybe the answer did not suit you. It is different from what I got. Words such as these can be difficult to interprete.

**http://web2.0calc.com/questions/answer-this-no-please-i-really-need-your-help**

Melody
Nov 15, 2015

#1**+10 **

Best Answer

I saw this one get answered yesterday (or earlier today) by 2 different guests. Didn't you like their answers?

OR is it just that you did not look for ages and notw you cannot find your question? If you were a member it would have been automatically put in your watchlist and you would have been able to find it really easily!

Let Pedro's age today be Y

and Petra's age today be X

If twice the present age of pedro (2Y) is decreased from petra's age 5 years ago (X-5), the result is 4.

(X-5) - 2Y = 4

X-5 - 2Y = 4

X - 2Y = 9 times 4 because I am going to use it with (2) below.

4X - 8Y = 36 (1)

Nine times pedro's age 3 years ago [9(Y-3)] exceeds 4 times Petra's present age [ 4X] by 4.

9(Y-3) - 4X = 4

9Y-27 - 4X = 4

9Y - 4X = 31

- 4X +9Y = 31 (2)

(1)+(2)

0+Y = 67

Pedro is 67 now

4X-8*67=36

4X=36+536

4X=572

X=143

Petra is 143 and Pedro is 67

check

If twice the present age of pedro (2Y) is decreased from petra's age years ago (X-5) , the result is 4.

138 - 2*67 = 138-134 = 4 good

Nine times pedro's age 3 years ago [9(Y-3)] 9*64 = 576 exceeds 4 times Petra's present age [ 4X=4*143=572] by 4.

576-572=4 good

So that is correct I believe.

So last year Petra was 142 and Pedro was 66 years old. Maybe they are sea turtles. Sea turtles live a long time.

----------------------------------------------------------------------------

Here is the earlier answer It was only a few post back so maybe the answer did not suit you. It is different from what I got. Words such as these can be difficult to interprete.

**http://web2.0calc.com/questions/answer-this-no-please-i-really-need-your-help**

Melody
Nov 15, 2015