If twice the present age of pedro is decreased from petra's age 5 years ago, the result is 4. Nine times pedro's age 3 years ago exceeds 4 times Petra's present age by 4. What are their ages last year?
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Let Pedro's age today be Y
and Petra's age today be X
If twice the present age of pedro (2Y) is decreased from petra's age 5 years ago (X-5), the result is 4.
(X-5) - 2Y = 4
X-5 - 2Y = 4
X - 2Y = 9 times 4 because I am going to use it with (2) below.
4X - 8Y = 36 (1)
Nine times pedro's age 3 years ago [9(Y-3)] exceeds 4 times Petra's present age [ 4X] by 4.
9(Y-3) - 4X = 4
9Y-27 - 4X = 4
9Y - 4X = 31
- 4X +9Y = 31 (2)
(1)+(2)
0+Y = 67
Pedro is 67 now
4X-8*67=36
4X=36+536
4X=572
X=143
Petra is 143 and Pedro is 67
check
If twice the present age of pedro (2Y) is decreased from petra's age years ago (X-5) , the result is 4.
138 - 2*67 = 138-134 = 4 good
Nine times pedro's age 3 years ago [9(Y-3)] 9*64 = 576 exceeds 4 times Petra's present age [ 4X=4*143=572] by 4.
576-572=4 good
So that is correct I believe.
So last year Petra was 142 and Pedro was 66 years old. Maybe they are sea turtles. Sea turtles live a long time.
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Here is the earlier answer It was only a few post back so maybe the answer did not suit you. It is different from what I got. Words such as these can be difficult to interprete.
http://web2.0calc.com/questions/answer-this-no-please-i-really-need-your-help
I saw this one get answered yesterday (or earlier today) by 2 different guests. Didn't you like their answers?
OR is it just that you did not look for ages and notw you cannot find your question? If you were a member it would have been automatically put in your watchlist and you would have been able to find it really easily!
Let Pedro's age today be Y
and Petra's age today be X
If twice the present age of pedro (2Y) is decreased from petra's age 5 years ago (X-5), the result is 4.
(X-5) - 2Y = 4
X-5 - 2Y = 4
X - 2Y = 9 times 4 because I am going to use it with (2) below.
4X - 8Y = 36 (1)
Nine times pedro's age 3 years ago [9(Y-3)] exceeds 4 times Petra's present age [ 4X] by 4.
9(Y-3) - 4X = 4
9Y-27 - 4X = 4
9Y - 4X = 31
- 4X +9Y = 31 (2)
(1)+(2)
0+Y = 67
Pedro is 67 now
4X-8*67=36
4X=36+536
4X=572
X=143
Petra is 143 and Pedro is 67
check
If twice the present age of pedro (2Y) is decreased from petra's age years ago (X-5) , the result is 4.
138 - 2*67 = 138-134 = 4 good
Nine times pedro's age 3 years ago [9(Y-3)] 9*64 = 576 exceeds 4 times Petra's present age [ 4X=4*143=572] by 4.
576-572=4 good
So that is correct I believe.
So last year Petra was 142 and Pedro was 66 years old. Maybe they are sea turtles. Sea turtles live a long time.
----------------------------------------------------------------------------
Here is the earlier answer It was only a few post back so maybe the answer did not suit you. It is different from what I got. Words such as these can be difficult to interprete.
http://web2.0calc.com/questions/answer-this-no-please-i-really-need-your-help