If y=kx14 and y=3√2 at x=81, what is the value of y at x=4?
y = k x^(1/4)
Let's start by finding k.
3sqrt(2) = k * (81)^(1/4)
3sqrt(2) = k * 3
k = sqrt(2)
y = sqrt(2) * 4^(1/4)
Can you take it from here? :))
=^._.^=
Thx, I get it now
+136 
