+0

+1
53
2
+103

If $$y=kx^{\frac{1}{4}}$$ and $$y=3\sqrt{2}$$ at $$x = 81$$, what is the value of $$y$$ at $$x = 4$$?

Sep 19, 2021

#1
+2240
+2

y = k x^(1/4)

Let's start by finding k.

3sqrt(2) = k * (81)^(1/4)

3sqrt(2) = k * 3

k = sqrt(2)

y = sqrt(2) * 4^(1/4)

Can you take it from here? :))

=^._.^=

Sep 19, 2021
#2
+103
+2

Thx, I get it now

NaturalDisaster  Sep 19, 2021