Using the distance formula, SQRT[(x2- x1)^2 + (y2- y1)^2], we have
((8-3)^2 + (12-4)^2))^(.5) =
(5^2 + 8^2)^(.5) = (25 + 64)^(.5) = (89)^(.5) =
$${\left({\mathtt{89}}\right)}^{\left({\mathtt{0.5}}\right)} = {\mathtt{9.433\: \!981\: \!132\: \!056\: \!603\: \!8}}$$
