Write an equation in slope-intercept from for the parallel to y=3x-2 that passes through the point (5,-2). Type your equation in form y=mx+b
Parallel lines have the same slope so the second line must have a slope of 3. We then have y=3x+b. We plug in the given point to find b.
y=3x+b
-2=3(5)+b
-2=15+b
b=-17
Therefore the equation is y=3x-17.