Help Me Please
Solve the problem.
Express the answer using proper significant figures and units. Refer to the periodic table as needed.
Consider the reaction 2 Al(s) + Fe2O3(s) → 2 Fe(I) + Al2O3(s). If 60.0 g of Al is reacted with excess Fe2O3, determine the amount (in moles) and mass (in grams) of Al2O3 produced. (MAl2O3= 101.96 g/mol)
Separate your answers with a semicolon.
Al atomic mass 26.98 gm/mole
60.0 / 26.98 = 2.22 moles of Aluminum (3 sig digits)
each 2 moles of Aluminum produce ONE mole of Aluminum oxide
2.22 moles Al / 2 moles Al/ Al2O3 = 1.11 moles Aluminum oxide
1.11 moles Aluminum Oxide * 101.96 g/mole = 113 gm aluminum oxide (3 sig digits)