Given DE||AB,AC=15,DC=10,EC=8. find BE
do you have a picture?
Im assuming its something like this: (I cant be sure I dont want to solve the wrong question.)
yes..its something like that only that
You should upload the actual picture.
only that what.
By intercept theorem,
\(\dfrac{\text{AC}}{\text{DA} }= \dfrac{\text{BC}}{\text{BE}}\\ \dfrac{15}{15-10} = \dfrac{8 + \text{BE}}{\text{BE}}\\ 15\text{BE} = 40 + 5\text{BE}\\ 10\text{BE} = 40\\ \text{BE}=4\)
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