Three cards are dealt at random from a standard deck of 52 cards. What is the probability that the first card is a 4, the second card is a \(\clubsuit\), and the third card is a 2?
[4/52]*[13/52]*[4/52]
=1/676
if with replacement
if without replacement ,
[4/52]*[12/48]*[3/36}
=1872
