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Help me, please

 

Find the Equation of the line that passes through (-3,2) that is perpendicular to the following: y=-3/2x+1

ManuelBautista2019  Dec 12, 2017
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The slope of the given line  = -3/2

 

So....the slope of a perp. line   will be the negative reciprocal  = 2/3

 

So...we have, using  (-3, 2)

 

y  = (2/3) ( x  -  -3)  +   2

 

y   =  (2/3)  ( x + 3)  + 2

 

y  = (2/3)x + 2  + 2

 

y  = (2/3)x  +  4

 

 

cool cool cool

CPhill  Dec 12, 2017

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