Find the sum of all values of $x$ such that $2^{x^2-3x-2} = 4^{x - 4}$.
Note that 4 = 2^2
(22)x-4 = 22x-8 now you can just equate the EXPONENTS and solve for 'x'
x^2 - 3x - 2 = 2x-8 can you take it from here???
+18 
