Identify the domain and range for problems 6 and 7 a ball was thrown into the air with an initial velocity of 72 feet per square second. The height of the ball after t seconds is represented by the equation h = 72𝑡 – 16𝑡2.

Guest Mar 24, 2018

#1**0 **

h = -16t^2 + 72t

The time that the ball is at the max height can be found as

-72 / [ 2 (-16) ] = -72 / -32 = 9/4 sec = 2.25 sec

And the max height is

-16(9/4)^2 + 72 (9/4) = 81 ft

The ball wil fall back to the ground at 2(9/4) = 18/4 = 9/2 sec = 4.5 sec

So.....the domain is from 0 seconds to 4.5 seconds

And the range is from 0 ft to 81 ft

Hre's a graph : https://www.desmos.com/calculator/i1dbl46fd9

CPhill Mar 25, 2018