We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
315
1
avatar

When the expression\(\) \(-2x^2-20x-53\) is written in the form \(a(x+d)^2+e\), where \(a\), \(d\), and \(e\) are constants, then what is the sum \(a+d+e\)?

 Jan 1, 2018
edited by Guest  Jan 1, 2018
 #1
avatar+101084 
+1

-2x^2 -  20x -  53   complete the square

 

-2   ( x^2   +  10x  +  25   +  53/2  - 25)

 

-2 [  (x + 5)^2  +  53/2  -  50/2 )

 

-2 [ (x + 5)^2  +  3/2  ] 

 

-2( x + 5)^2  -  3

 

a  =  -2         d  =  5           e   =  -3

 

And their sum  =  0

 

 

cool cool cool

 Jan 2, 2018

8 Online Users

avatar
avatar
avatar