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When the expression\(\) \(-2x^2-20x-53\) is written in the form \(a(x+d)^2+e\), where \(a\), \(d\), and \(e\) are constants, then what is the sum \(a+d+e\)?

 Jan 1, 2018
edited by Guest  Jan 1, 2018
 #1
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-2x^2 -  20x -  53   complete the square

 

-2   ( x^2   +  10x  +  25   +  53/2  - 25)

 

-2 [  (x + 5)^2  +  53/2  -  50/2 )

 

-2 [ (x + 5)^2  +  3/2  ] 

 

-2( x + 5)^2  -  3

 

a  =  -2         d  =  5           e   =  -3

 

And their sum  =  0

 

 

cool cool cool

 Jan 2, 2018

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