In triangle ABC, cos A = 2/3 and cos B = 2/7. Given the perimeter of the triangle ABC is 24, compute the area of triangle ABC.
From the 2 angles and the perimeter of 24, the 3 sides are:
a =8, b =7 and c=9 for a perimeter of 24
Using Heron's formula:
Area = 26.833
