We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
467
4
avatar

Koopa Troopa throws a dart at a parallelogram-shaped board, shown below. You know that $BC=10$, $AE=4$, and angle $BAD=45^\circ$. Assuming the dart will hit all spots on the board with equal likelihood, what is the probability the dart lands in triangle $ABE$? Express your answer as a decimal between 0 and 1.sad

 Aug 3, 2018
 #1
avatar
0

Where is your picture??!!

 Aug 3, 2018
 #2
avatar
0

I will insert one

 Aug 3, 2018
 #3
avatar
0

Here is the picture

 

HERE IS THE PICTURE IF NEEDED

 Aug 3, 2018
 #4
avatar
0

Since angle BAD =45 degrees, so is angle ABE, because it is a right triangle. Its height BE=4

 

Area =BC x BE(Height)

          = 10 x 4

          = 40 units^2 - the area of parallelogram.

 

Area of triangle ABE =1/2 x 4 x 4 =8 units^2

The probability that the dart will land in triangle ABE =8/40 =0.2

 Aug 3, 2018
edited by Guest  Aug 3, 2018

26 Online Users

avatar
avatar