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3x-8y=24 y=x-8 solving systems by substitution

Guest Apr 25, 2017

Best Answer 

 #1
avatar+771 
+2

3x-8y=24 and y=x-8 by substitution

 

Plug y=x-8 into 3x-8y=24

3x-8(x-8)=24

3x-8x+64=24

-5x+64=24

Subtract 64 from both sides

-5x=-40

Divide both sides by -5

x=8

 

Plug x=8 into y=x-8

y=8-8

y=0

 

x=8, y=0

(8,0)

AdamTaurus  Apr 25, 2017
 #1
avatar+771 
+2
Best Answer

3x-8y=24 and y=x-8 by substitution

 

Plug y=x-8 into 3x-8y=24

3x-8(x-8)=24

3x-8x+64=24

-5x+64=24

Subtract 64 from both sides

-5x=-40

Divide both sides by -5

x=8

 

Plug x=8 into y=x-8

y=8-8

y=0

 

x=8, y=0

(8,0)

AdamTaurus  Apr 25, 2017

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