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A 3.00-kg objects has a velocity ( 6i - 1 k ) m/s .
a) What is its kinetic energy at this moment ?
b) what is thw work done on the object if its velocity changes to ( 8 i + 4 j ) m/s .

 Nov 8, 2020
 #1
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KE = 1/2 mv^2          v = sqrt ( 6^2 + (-1)^2) ) = sqrt37    m= 3.00

 Nov 8, 2020
 #2
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Work = change in KE

Initial KE     1/2 m ( 6^2 + (-1)^2)

final KE        1/2 m ( 8^2 + 4^2)

 Nov 8, 2020
 #3
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thank you 

Guest Nov 8, 2020

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