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Does this say $\frac{y+z}{z}$ . If so, try to break it up into $\frac{y}{z}+\frac{z}{z}$ , so   $\frac{y}{z}+1.$ Therefore, we have    $4y=3z, y=\frac{3}{4}z$ and $\frac{3z}{4}*\frac{1}{z}=\frac{3}{4}$ , so     $1+\frac{3}{4}=\boxed{1\frac{3}{4}}.$