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log4(x-6)=1-log4(x-3)

 Feb 21, 2019

Best Answer 

 #1
avatar+17331 
+2

log4(x-6) + log4(x-3) =1

log4((x-6)(x-3) = 1

log4(x^2-9x+18) = 1  

x^2-9x+18 = 4

x^2-9x+14 = 0

(x-7)(x-2) = 0      x = 7 and 2   but since there are no logs of negatives     x = 7

 Feb 21, 2019
edited by Guest  Feb 21, 2019
 #1
avatar+17331 
+2
Best Answer

log4(x-6) + log4(x-3) =1

log4((x-6)(x-3) = 1

log4(x^2-9x+18) = 1  

x^2-9x+18 = 4

x^2-9x+14 = 0

(x-7)(x-2) = 0      x = 7 and 2   but since there are no logs of negatives     x = 7

ElectricPavlov Feb 21, 2019
edited by Guest  Feb 21, 2019

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