Factorize by remarkable identities:49(x+1)squared minus 25
"Factorize by remarkable identities:49(x+1)squared minus 25"
\(49(x+1)^2-25\rightarrow(7x+7)^2-5^2\rightarrow(7x+7+5)(7x+7-5)\rightarrow(7x+12)(7x+2)\)
49 (x+1)^2 = 25
(x+1)^2 = 25/49
x+1 = + - 5/7
x = 5/7 -1 or -5/7 -1
x = -2/7 , -12/7
49(x+1)squared minus 25
\(\large 49(x+1)^2-25=7^2(x+1+5)(x+1-5)\)
\(=7^2(x^2+x-5x+x+1-5+5x+5-25)\)
\(=7^2(x^2+2x-24) \)
\(x=1\pm\sqrt{1+24} \ \Rightarrow x_1=6 \ \wedge \ x_2=-4\)
\(\large =7\times 7 \times (x-6)\times (x+4) \)
!
Not correct! Here comes the correction.
49(x+1)squared minus 25 Factorize!
\(\large 49(x+1)^2-25\)
\((7(x+1))^2-25=(7(x+1)+5)\times (7(x+1)-5)\)
\(=(7x+12)\times (7x+2)\)