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If $f(x)=2/x+1$ , then what is the value of $f^-1$(1/5)$

 

 

I would like the answer soon if you can 

 Jan 23, 2021
 #1
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First you'll have to find the inverse function

y = 2/ (x+1)      or is it     2/x    +1 ?      people often forget parentheses which are necessary.....

 Jan 23, 2021
 #2
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IF it's:  y = 2/(x+1) 

x = 2 / (y+1)

y+1 = 2/x

y = 2/x    -1     is the f-1

y = 2/(1/5) -1 = 9

 Jan 23, 2021

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