We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
129
1
avatar

The least common multiple of two positive integers is 7!, and their greatest common divisor is 9. If one of the integers is 315, then what is the other?

 Jun 26, 2018
 #1
avatar
0

Let the other number = N

 

GCD[N, 315] = 9, solve for N

N = 9

LCM[N, 315] =7!, solve for N

N = 16

So, in order to satisfy both GCD and LCM, then:

N = 9 x 16 = 144, so that:

GCD[144, 315] = 9, and

LCM[144, 315] =7!, So;

N = 144 - the second number.

 Jun 26, 2018

3 Online Users

avatar