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Given that the point \((9,7)\) is on the graph of \(y = f(x)\), there is one point that must be on the graph of \(2y=\frac{f(2x)}2+2\). What is the sum of coordinates of that point?

 Dec 13, 2018

Best Answer 

 #1
avatar+5076 
+2

\(2y=\dfrac{f(2x)}{2}+2\\ y = \dfrac{f(2x)}{4}+1\\ f\left(2 \dfrac 9 2\right)=f(9)=7\\ y = \dfrac{7}{4}+1=\dfrac{11}{4}\\ (x,y) = \left(\dfrac 9 2,~\dfrac{11}{4}\right)\)

 

\(x+y = \dfrac{18+11}{4} = \dfrac{29}{4}\)

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 Dec 13, 2018
 #1
avatar+5076 
+2
Best Answer

\(2y=\dfrac{f(2x)}{2}+2\\ y = \dfrac{f(2x)}{4}+1\\ f\left(2 \dfrac 9 2\right)=f(9)=7\\ y = \dfrac{7}{4}+1=\dfrac{11}{4}\\ (x,y) = \left(\dfrac 9 2,~\dfrac{11}{4}\right)\)

 

\(x+y = \dfrac{18+11}{4} = \dfrac{29}{4}\)

Rom Dec 13, 2018

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