What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?
k=3
112-(3*(-3))=121
Then
121 = 112 - k (-3) subtract 112 from each side
9 = -k (-3) divide both sdes by -3
-3 = -k multiply through by -1
3 = k