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x​2​​−d=(x+c)(x−4)x

What is the value of c and d

 Feb 6, 2016

Best Answer 

 #3
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+5

Evaluate f(x) = 14-0.5x

f(30)=14 - .5*30

f(30)=14 - 15

f(30)= -1

 Feb 6, 2016
 #1
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+5

Solve for c: x^2-d = x (x-4) (c+x) x^2-d = (x-4) x (c+x) is equivalent to (x-4) x (c+x) = x^2-d: x (x-4) (c+x) = x^2-d Divide both sides by x (x-4): c+x = (x^2-d)/(x (x-4)) Subtract x from both sides: Answer: | | c = (x^2 - d) / (x(x-4)) - x

 

Solve for d: x^2-d = x (x-4) (c+x) Subtract x^2 from both sides: -d = x (x-4) (c+x)-x^2 Multiply both sides by -1: Answer: | | d = x^2 - x(x-4) (c+x)

 Feb 6, 2016
 #2
avatar
+5

Evaluate f(x) = 14-0.5x

f(30)=

 Feb 6, 2016
 #3
avatar
+5
Best Answer

Evaluate f(x) = 14-0.5x

f(30)=14 - .5*30

f(30)=14 - 15

f(30)= -1

Guest Feb 6, 2016

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